Y-16=2x^2+8x

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Solution for Y-16=2x^2+8x equation: 



-16=2Y^2+8Y

We move all terms to the left:

-16-(2Y^2+8Y)=0

We get rid of parentheses

-2Y^2-8Y-16=0

a = -2; b = -8; c = -16;
Δ = b2-4ac
Δ = -82-4·(-2)·(-16)
Δ = -64
Delta is less than zero, so there is no solution for the equation

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